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eaz_coding
[Baekjoon] 미세먼지 안녕! 본문
문제
https://www.acmicpc.net/problem/17144
풀이
import sys
input = sys.stdin.readline
r, c, time = map(int, input().split())
arr = []
purifier = []
for i in range(r):
arr.append(list(map(int, input().split())))
for j in range(c):
if arr[i][j] == -1:
purifier.append((i, j))
directions = [(0, 1), (1, 0), (0, -1), (-1, 0)]
opposite = [(0, 1), (-1, 0), (0, -1), (1, 0)]
def area(x, y):
return 0 <= x < r and 0 <= y < c
def diffusion(arr):
tmp = [[[0,0] for _ in range(c)] for _ in range(r)]
for i in range(r):
for j in range(c):
if arr[i][j] != 0 and arr[i][j] != -1:
cnt = 0
v = arr[i][j] // 5
for dx, dy in directions:
ni, nj = dx+i, dy+j
if area(ni, nj):
if arr[ni][nj] != -1:
tmp[ni][nj][1] += v
cnt += 1
tmp[i][j][0] = v*cnt
return tmp
def change(tmp):
global arr
for i in range(r):
for j in range(c):
if arr[i][j] == -1:
continue
if arr[i][j] - tmp[i][j][0] + tmp[i][j][1] < 0:
arr[i][j] = 0
else:
arr[i][j] = arr[i][j] - tmp[i][j][0] + tmp[i][j][1]
def purify():
global arr
for x in range(2):
i, j = purifier[x]
tmp = 0
if x == 0:
for di, dj in opposite:
while True:
ni, nj = di+i, dj+j
if area(ni, nj):
t = arr[ni][nj]
if arr[ni][nj] == -1:
break
arr[ni][nj] = tmp
tmp = t
i, j = ni, nj
else:
break
else:
for di, dj in directions:
while True:
ni, nj = di+i, dj+j
if area(ni, nj):
t = arr[ni][nj]
if arr[ni][nj] == -1:
break
arr[ni][nj] = tmp
tmp = t
i, j = ni, nj
else:
break
for _ in range(time):
tmp = diffusion(arr)
change(tmp)
purify()
answer = 2
for i in arr:
answer += sum(i)
print(answer)